(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)

(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)

Matematika Question.

77 + 88 × 8 ÷ 2 = ?

Nt = [.]​

Question.

77 + 88 × 8 ÷ 2 = ?

Nt = [.]​

77 + 88 × 8 ÷ 2

= 77 + 88 × 8 ÷ 2

= 77 + (88 × 8 ÷ 2)

= 77 + 352

= 429

[tex]\bold{\mathbb{\color{ff0000}{♡} \color{ff4000}{♡}\color{ff8000}{♡}\color {ffc000}{♡}\color{ffff00}{♡}\color{c0ff00}{♡}\color {80ff00}{♡}\color{40ff00}{♡}\color {00ff00}{♡}\color{00ff40}{M}\color{00ff80}{a}\color {00ffc0}{s} \: \color{00ffff}{R}\color {00c0ff}{y}\color{0080ff}{a}\color{0040ff}{n}\color {0000ff}{♡}\color{4000ff}{♡}\color{8000ff}{♡}\color{c000ff}{♡}\color{ff00ff}{♡}\color {ff00c0}{♡}\color{ff00a0}{♡}\color{ff0080}{♡}\color{ff0040}{♡}}}[/tex]

Jawaban:

77 + 88 × ( 8 ÷ 2 )

= 77 + ( 88 × 4 )

= 77 + 352

= 429

Dahulu kan pembagian dan perkalian lalu baru penjumlahan

[answer.2.content]